I am making a PHP Journal through a form, but no matter what I do, it always comes up as successfully posted. I've tried using empty() and null but I'm not sure what I'm doing wrong.
Here is the HTML for the form:
<form action="journal_post.php" method="post">
<p>Give your entry a title.</p>
<input class="input" type="text" name="title" />
<p>What is your mood today?</p>
<input class="input" type="text" name="mood" />
<p>Now please tell me about your day.</p>
<textarea class="input" name="entry" rows="12" cols="75" type="text"> </textarea>
<br>
<br>
<input class="submit" type="image" src="submit.png" name="submit" value="Submit" />
<form>
Here is the PHP:
<?php
$servername = "localhost";
$username = "root";
$password = "blahblah";
debug_to_console($password);
//Establishing Connection with Server
$connection = mysql_connect($servername, $username, $password);
//Selecting Database from Server
$journal_db = mysql_select_db("journal_db", $connection);
if(isset($_POST['submit'])){
//Fetching variables of the form which travels in URL
$title = $_POST['title'];
$mood = $_POST['mood'];
$entry = $_POST['entry'];
if($title !=''||$entry !=''){
//Insert Query of SQL
$query = mysql_query("insert into entrys(j_title, j_mood, j_entry) values ( '$title', '$mood', '$entry')");
echo "<br/><br/><span>Journal entry recorded..!!</span>";
}
else{
echo "<p>Insertion Failed <br/> Some Fields are Blank....!!</p>";
}
}
//Closing Connection with Server
mysql_close($connection);
?>
