How to insert part of column in MySQL using php ? For example,my column table in sql are : code,Title,Cr,prerequisite,Addit,Grade I used table to fetch the data in php , but Addit and Grade is empty . I want user to insert them the other column is fixed with specific data .
How to insert in just in Addit and Grade ?
The problem i face in this code is that the insert data is coming alone in row not in Addit and Grade with the names of course .
I want from student to define the grade of course name university studies weather A,B,C,D. And ,to define weather students complete or not complete this course.
enter code here
<html>
<head>
</head>
<body>
<form action="insert.php" name="frmAdd" method="post">
<table border='1' cellpadding='5' cellspacing='1' id='mytable'>
<tr align='center'>
<th>code</th>
<th>Title</th>
<th>Cr</th>
<th>prerequisite</th>
<th>Addi</th>
<th>grade</th>
</tr>
<?php
error_reporting(0);
$sql="select code,Title,Cr,prerequisite,Addit,Grade from study_p";
$result=mysql_query($sql);
while ($row = mysql_fetch_array($result))`
$code = $row['code'];
$Title = $row['Title'];
$cr = $row['Cr'];
$pre = $row['prerequisite'];
$addit= $row['Addit'];
$grade = $row['Grade'];
echo "<tr class='edit_tr' id='$id'>
<td class='edit_td'>
<span class='text' id='one_$ssn' >$code </span>
<input type='text' class='editbox_search' id='one_input_$ssn'
value='$code ' >
</td>
<td class='edit_td'>
<span class='text' id='two_$ssn' >$Title</span>
<input type='text' class='editbox_search' id='two_input_$ssn'
value='$Title' >
</td>
<td class='edit_td'>
<span class='text' id='three_$ssn' >$cr</span>
<input type='text' class='editbox_search' id='three_input_$ssn'
value='$cr' >
</td>
<td class='edit_td'>
<span class='text' id='three_$ssn' >$pre</span>
<input type='text' class='editbox_search' id='three_input_$ssn'
value='$pre' >
</td>
<td class='edit_td'>
<span class='text' id='three_$ssn' >$addit</span>
<select name='Addit' id='addit'>
<option value='A'>Completed</option>
<option value='B'>Not complate</option>
</select>
</td>
<td class='edit_td'>
<span class='text' id='three_$ssn' >$grade</span>
<select name='Grade' id='grade'>
<option value='A'>A</option>
<option value='B'>B</option>
<option value='C'>C</option>
<option value='D'>D</option>
<option value='F'>F</option>
</select>
</td>
</tr>";
}
?>
<p><input type="submit" value="Add Link"></p>
</tr>
</table>
</div>
insert.php
enter code here
<?php
$usr = "";
$pwd = "";
$db = "adv";
$host = "localhost";
$cid = mysql_connect($host,$usr,$pwd);
if (!$cid) { echo("ERROR: " . mysql_error() . "
"); }
?>
<?php
if ($_SERVER['REQUEST_METHOD'] == "POST") {
$addit= $_POST['Addit'];
$grade = $_POST['Grade'];
$sql = " INSERT INTO study_p";
$sql = $sql . " (code,Title,Cr,prerequisite,Addit,Grade) VALUES ";
$sql = $sql . " ('','','','','$addit', '$grade') ";
$result = mysql_db_query($db,"$sql",$cid);
if (!$result) {
echo("ERROR: " . mysql_error() . "
$sql
"); }
echo ("New Link Added
");
}
mysql_close($cid);
?>
sql
enter code here
CREATE TABLE IF NOT EXISTS `study_p` (
`Study_pID` int(25) NOT NULL,
`code` varchar(25) DEFAULT NULL,
`Title` varchar(100) DEFAULT NULL,
`Cr` int(200) DEFAULT NULL,
`prerequisite` varchar(25) DEFAULT NULL,
`Addit` varchar(25) DEFAULT NULL,
`Grade` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
insert into studyplancourses values(2, 'UNS 100', 'University Study
Skills', 3, 'No Prerequisite', NULL, ''),
insert into studyplancourses values(3, 'ENG 100', 'English I', 3, 'ELI
Exit
Test or TOEFL 50', NULL, ''),
