douao8204 2015-09-23 18:32
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PHP - 使用imagejpeg作为背景

I have loaded an image in a variable like this :

$img = imagecreatefromjpeg('my_image.jpg');

Now I want to use that image variable as a background for an html element. I tried this :

<div id="container" style="background:<?php imagejpeg($img);?>;"></div>

And I failed miserably. I don't know how to proceed.

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2条回答 默认 最新

  • douyan8266 2015-09-23 18:40
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    I am not sure what's your ultimate goal, but why not do something like this:

    $img = my_image.jpg;
    <div id="container" style="background-image: url(<?=$img?>);"></div>
    
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