douzhi1919 2015-05-29 14:48
浏览 93

如何使用PHP解析URL中的JSON

I have this URL:

http://server.com/api.php?results

{"Name":"Pit, Loka","Current":{"Item":"16","test":"test","test":"84","test":"ok"}}

I guess the PHP Example is:

<?php
$file = file_get_contents("http://server.com/api.php?results=item");
$data = json_decode($file);
print_r($data);
?>

but I can't get any results.
How can I solve this problem?

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1条回答 默认 最新

  • dozc1071 2015-05-29 15:24
    关注
    <?php
    $file = file_get_contents("http://server.com/api.php?results=item");
    $data = json_decode($file);
    
    $name = $data->Name; // "Name":"Pit, Loka"
    $current = $data->Current->Item; //"Current":{"Item":"16","test":"test","test":"84","test":"ok"}
    
    foreach ($current as $currentX) {
        echo $currentX->Item;
    }
    ?>
    

    It should work... please test.

    评论

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