doumu1212 2014-12-19 06:20
浏览 25

检查代码时不断出现语法错误

This is what i entered in the code checker it is wracking my brain to get this done. It keeps telling me I have

Parse error: syntax error, unexpected T_LNUMBER, expecting T_VARIABLE or '$' on line 8

$servername = "localhost";
$username = "user";
$password = "pass";
$db= "db";
$tbl_name = "usermanagement";


$conn =  mysql_connect($localhost, $user, $pass);
mysql_select_db($db);

if ( $conn->connect_error)  {
    die("Connection failed:  " .  $conn->connect_error);
}
echo "Connected successfully";
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2条回答 默认 最新

  • duan4369 2014-12-19 06:28
    关注

    I think you want to change this:

    $conn->connect_error
    

    to this:

    mysql_error()
    

    Also i would use the defined variable like this:

    $conn =  mysql_connect($servername, $username, $password);
    

    Since you're using mysql_* API and not mysqli_* where you can use this: $mysqli->connect_error because then you have a Object!.

    Also i would recommend you to use mysqli_* or PDO

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