从开始日期到结束日期，打印第三个变量的计数

Question

I have a start date as current date, which is stored in an array and the date 5 days back which is the end date.

Suppose the start date is 2014-12-03 and end date is 2014-11-28, so I have to print the count of a variable resulting from foreach, $value->user_source_history_date

And the process should run till the defined number lets say 30, where there are 30 dates in an array.

for($i=0; $i<=30; $i++)
{
$temp = strtotime("-5 days")
$dates = date("Y-m-d" , $temp)

}

Here I am iterating through 30 days, to get blocks of 5 days.

Lets say from a start date and end date, in the database field, user_source_history_dates, there are some 10 entries. So I need that count i.e 10 And the entries look like this:

2014-12-02 16:07:42
2014-12-02 16:07:42
2014-12-02 16:07:42
2014-12-02 16:07:42
2014-11-29 13:22:31
2014-11-29 13:22:31
2014-11-29 13:22:31

The start date would be 2014-12-03 and the end date would be 2014-11-28. So from the data above, I should get the count as 7.

My problem is how should I increment the count of $value->user_source_history_date

Also one of the problem is when the loop iterates, the end date previous iteration should become start date of next iteration.

One thing that I can do is use SQL query to get the data from a particular date block. Say something like this:

SELECT * FROM events WHERE datum BETWEEN '2011-4-6' AND '2011-4-12';

Answer 1

Based on OP comment, I hope I undersood him:

for ($i = 0; $i <= 30; $i++) {
    $temp = strtotime("-5 days");
    //Store dates in an array
    $dates[] = date("Y-m-d", $temp);
}
echo "The cound of dates: " . count($dates)."<br />";
var_dump($dates);