从另一个类中的静态函数调用时，PHP类构造函数未运行

Question

I am currently stamped and i can't see where I have done it wrong. I have a static function request() below:

private static function request(){

   if($_SERVER['REQUEST_METHOD']=='GET'){

       $data = RunData::get('cmd');

   }

which calls a static function get() which in turn calls a private function clean() which uses variables set in the class constructor loading an Injected class Sanitize

class RunData {

    public static $sanitize;

    public function __construct( Sanitize $sanitize ){

        self::$sanitize = $sanitize;

    }

   private static function clean($variable_array){    

        if(is_array($variable_array)){

            $filters = array('string' => 'sanitize_string');

            return self::$sanitize->filter($variable_array, $filters);   

        }
    }

    public static function get($variable){

        if(self::clean($_GET)){

            return $_GET[$variable];

        }

    }


}

but when I run I get this error.

Fatal error: Call to a member function filter() on a non-object

This filter function is loaded from the Sanitize Class which is injected into the constructor.

What possibly have I missed??? The constructor doesn't seem to be running

Thanks

Answer 1

You're correct, __construct() is not called when the class is invoked statically. You'll need to set up the object manually by injecting that Sanitize class via some sort of setup method before calling the method.

For example:

public static function setSanitizeClass(Sanitize $sanitise)
{
    self::$sanitize = $sanitize;
}

Then:

RunData::setSanitizeClass(new Sanitize());
$data = RunData::get('cmd');