无法通过XML文件解析器读取任意文件

Question

So I've wanted to create a very basic XML file parser that imports XML styles.

<?php
//error_reporting(0);

$XSLT = new XSLTProcessor();
$XML = new DOMDocument();
$XSL = new DOMDocument();

$XSL->load($_GET['file']);
$XSLT->importStyleSheet($XSL);

print $XSLT->transformToXML($XML);

Now I need to read an arbitrary file like this:

http://localhost/parser.php?file=style.xml

Given that I find it hard to troubleshoot as to why I cannot seem to read a .txt file on the local filesystem in the same directory.

<xsl:stylesheet xmlns:xsl='http://www.w3.org/1999/XSL/Transform'>
    <xsl:template match='/'>
        <xsl:copy-of select="document('message.txt')"/>
    </xsl:template>
</xsl:stylesheet>

Answer 1

The document() function requires well-formed XML. You can't use it to read a plain text document. Try using it to read an XML document in the same directory. It should work:

<xsl:copy-of select="document('message.xml')"/> <!-- message.xml is well formed XML -->