dplm47571
dplm47571
2014-06-06 02:42
浏览 53

将数据从CasperJS脚本发送到PHP

I’m trying to get data from CasperJS like this:

Contents of file.php:

$casperjs = "casperjs";
$script = 'add_site.js';
$arg0 = $_POST['new_site'];  
$command = "$casperjs $script $arg0";
$result = shell_exec($command);
echo $result;

Contents of casperjs.js:

casper.then(function() {
  // some code
  utils.dump(JSON.stringify(site));
});
casper.run(function() {
  this.exit();
});

I have nothing on output.

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我正在尝试从 CasperJS 是这样的:

file.php 的内容:

  $  casperjs =“casperjs”; 
 $ script ='add_site.js'; 
 $ arg0 = $ _POST ['new_site'];  
 $ command =“$ casperjs $ script $ arg0”; 
 $ result = shell_exec($ command); 
echo $ result; 
   
 
 

的内容 code> casperjs.js

  casper.then(function(){
 // some code 
 utils.dump(JSON.stringify(site)  ); 
}); 
casper.run(function(){
 this.exit(); 
}); 
   
 
 

我什么都没有 输出。

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2条回答 默认 最新

  • duanmu5641
    duanmu5641 2014-06-06 02:53
    已采纳

    Not 100% on CasperJS, but looking at your PHP code try using json_encode in your script like this:

    $casperjs = "casperjs";
    $script = 'add_site.js';
    $arg0 = $_POST['new_site'];  
    $command = "$casperjs $script $arg0";
    $result = shell_exec($command);
    echo json_encode($result);
    

    Also try setting explicit JSON headers for your output like this:

    $casperjs = "casperjs";
    $script = 'add_site.js';
    $arg0 = $_POST['new_site'];  
    $command = "$casperjs $script $arg0";
    $result = shell_exec($command);
    $json_data = json_encode($result);
    header('X-JSON: (' . $json_data . ')');
    header('Content-type: application/x-json');
    echo $json_data;
    
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  • dongmu1951
    dongmu1951 2014-06-06 15:43

    I had a problem with casperjs.

    PHP must be so:

    $casperjs = "/home/k/kreker92/casperjs/bin/casperjs";
    $script = 'add_site.js';
    $arg0 = $_POST['new_site'];
    putenv("PHANTOMJS_EXECUTABLE=/home/k/kreker92/phantomjs/bin/phantomjs");
    $command = "$casperjs $script $arg0";
    $result = shell_exec($command);
    $json_data = json_encode($result);
    
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