dqt20140129 2014-05-19 02:49
浏览 60

显示已登录用户的用户名以及其他人的注册/登录链接

I really need help for my login script. I want to show some PHP codes to show username for logged-in users else for others show only login/signup link.

Codes given below.

/*---Logged in user's homepage---*/


<?PHP

require_once('../lib/connections/db.php');

include('../lib/functions/functions.php');

checkLogin('2');

$getuser = getUserRecords($_SESSION['user_id']);

?>

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" />

<title><?=$getuser[0]['username'];?>'s Profile Page | HDS Web</title>

<?php include('../headother.php'); ?>

<div style="background:#FFFFFF; padding-bottom:150px; padding-top:15px;">


/*----User's photo and details section goes below----*/


<div style="float:left; width:600px;">  

<p>
Welcome <?php if(empty($getuser[0]['first_name']) || empty($getuser[0]['last_name'])){echo $getuser[0]['username'];} else {echo $getuser[0]['first_name']." ".$getuser[0]['last_name'];} ?></p>                       

 <? displayUserImg($getuser[0]['id']); ?>

</div>


/*---User's navigation menu section goes below---*/


<div style="float:right; width:200px;"> 

    <a href="index.php">Home</a> | <? if (!empty($getuser[0]['thumb_path'])){echo "<a href='manage_photo.php'>Manage My Photo</a> | ";} else {echo "<a href='upload_photo.php'>Upload Photo</a> | ";} ?>

<a href="change_pass.php">change password</a> | 

<a href="edit_profile.php">Edit Profile</a> 

| <a href="log_off.php?action=logoff">sign out</a></div></td>


    </div>
    <?php include('../footer.php');?>


</body>
</html>
  • 写回答

1条回答 默认 最新

  • dtujfmfs06058 2014-05-19 03:40
    关注

    You can do like this:

    if(isset($_SESSION['user_id'])) {
  // detected a valid user
  ?>
  <p>Welcome <?php if(empty($getuser[0]['first_name']) || empty($getuser[0]['last_name'])){echo $getuser[0]['username'];} else {echo $getuser[0]['first_name']." ".$getuser[0]['last_name'];} ?></p>
  <?php                  
  displayUserImg($getuser[0]['id']);
} else {
  // didn't login, show login link
  echo '<p><a href="login.php">Login Link</a></p>';
}

    Mentioned in comment, checking $_SESSION['user_id'] does not guarantee accurate result, as the function may not return a user object when the user_id is not found in database. It is better to determine from the return value of getUserRecords().

    Side Notes:

    • Where is your DOCTYPE ?
    • Your HTML maybe invalid, without closing <head> and opening <body> tags (well, it may be contained in your included files. Who knows?)
    • stop using inline CSS
    • recommend not to use <? . Use <?php instead
    评论

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