dpm91915 2013-08-12 16:56
浏览 22
已采纳

在sql查询中不起作用

i have two tables in my db .. one is Messages and the other is Contacts... both tables contain the mobile_number field.. in Contacts table there is no duplicate numbers ... but in Messages tables there are several duplicate numbers in mobileNo field...what i am doing is write now i am selecting the distinct mobile numbers from the Messages tables and then i am comparring the distinct numbers from the contacts table ... so if the messages_mobileNo is found on the contacts table then give me the contact name against the number otherwise messages_mobileNo ... so the problem is distinct not working .. i am not able to get the distinct numbers from the Messages table ... it is showing me the duplicate numbers

here is my query

 SELECT DISTINCT Message.mobileNo,
            Contact.mobileNo,
            Contact.workNo,
            Contact.homeNo,
            Contact.other,
            Contact.name,

            Message.body,
            Message.idTextMessage
FROM cakephp_db.textmessage AS Message
LEFT JOIN cakephp_db.contacts AS Contact ON (Message.user_id = Contact.user_id
                                         AND ((Message.mobileNo = Contact.mobileNo)
                                              OR (Message.mobileNo = Contact.workNo)
                                              OR (Message.mobileNo = Contact.homeNo)
                                              OR (Message.mobileNo = Contact.other)))
 WHERE Message.User_id = 23
 ORDER BY Message.idTextMessage DESC LIMIT 6
  • 写回答

3条回答 默认 最新

  • dongyi1939 2013-08-12 17:01
    关注

    So your trying to get the last 6 messages of a person if I'm right?

     SELECT Message.mobileNo,
                Contact.mobileNo,
                Contact.workNo,
                Contact.homeNo,
                Contact.other,
                Contact.name,
    
                Message.body,
                Message.idTextMessage
    FROM cakephp_db.textmessage AS Message
    LEFT JOIN cakephp_db.contacts AS Contact ON Message.user_id = Contact.user_id
                                             AND Message.mobileNo IN (Contact.mobileNo, Contact.workNo, Contact.homeNo, Contact.other)
     WHERE Message.User_id = 23
    GROUP BY Message.mobileNo
     ORDER BY Message.idTextMessage DESC LIMIT 6
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 delta降尺度计算的一些细节,有偿
  • ¥15 Arduino红外遥控代码有问题
  • ¥15 数值计算离散正交多项式
  • ¥30 数值计算均差系数编程
  • ¥15 redis-full-check比较 两个集群的数据出错
  • ¥15 Matlab编程问题
  • ¥15 训练的多模态特征融合模型准确度很低怎么办
  • ¥15 kylin启动报错log4j类冲突
  • ¥15 超声波模块测距控制点灯,灯的闪烁很不稳定,经过调试发现测的距离偏大
  • ¥15 import arcpy出现importing _arcgisscripting 找不到相关程序