Suppose, in Yii framework if any other parameter has to be sent to any other file. How can I do this. If from admin.php I have to send another variable to update.php. How can I do this
1条回答 默认 最新
- dongxi0605 2013-08-13 04:32关注
If
update.php
is child view insideadmin.php
, you can do follow onadmin.php
$this->renderPartial('update', array('param1'=>'value1', 'param2'=>'value2', ...))
(noted this example
update.php
is same folder level withadmin.php
)If both of files came from two different actions, or they have their own URL look like below
public function actionAdmin(){ ...; $this->render('admin');} public function actionUpdate(){ ...; $this->render('update');}
you have to treat it as query string
admin.php
Example:
<?php echo CHtml::link('Go to Update',array( 'controller/update', 'param1'=>'value1', 'param2'=>'value2', ...)); ?>
More about Yii URL Managger and querystring
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