dongshuobei1037 2013-05-14 16:23
浏览 45

我试图将其重写为mysqli查询,但我一直收到错误

I wrote a query in PHP and mysql and it works fine and returns data I am just trying to re-write it as a Mysqli function.

This is what I come up with but I get a 500 error with the file.

if (mysqli_connect_errno()) {
    printf("Could not talk to the database: ", mysqli_connect_error());
    exit();
}
$query("SQL QUERY WORKS FINE");
$data = array();
if ($result = $con->query($query)) {
    $tempData = array();
    while ($row = $result->fetch_object()) {
        $tempData = $row;
        array_push($data, $tempData);
    }
    echo json_encode($myArray);
}
/* free result set */
$result->close();
$con->close();
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  • doumangzhen7204 2013-05-14 16:27
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    First problem I see is that you are trying to json_encode a variable that does not exist. change $myArray to $tempData ?

    If your debugging is turned off the error message would go into error_log saying undefined variable $myArray

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