AJAX post方法：变量不会传递给目标php

Question

I am trying to send two pieces of info to a php. 1-) tent = zuzu 2-) zart = gagi

target php simply echoes what I send so that I can check if it's working. This is the javascript:

    function boka ()
{
var mesparam = "tent=zuzu&zart=gagi";
if (window.XMLHttpRequest){xmlhttp=new XMLHttpRequest();}
else {xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");}
xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) {document.getElementById("response").innerHTML=xmlhttp.responseText;} }
xmlhttp.open("POST","/mysite/oxifa/oxifat.php?tent=zuzu&zart=gagi",true); 
//xmlHttp.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
//xmlhttp.setRequestHeader("Content-length", mesparam.length);
//xmlHttp.setRequestHeader("Connection", "close");
xmlhttp.send(mesparam);
}

This is oxifat.php that recieves the request:

    <?php
echo " sign1 <br>";


echo next($_POST);
echo next($_POST);
echo next($_POST);
echo next($_POST);
echo next($_POST);
echo $_POST['tent'];
echo $_POST['zart'];
echo $_REQUEST['tent'];
echo $_REQUEST['zart'];

echo "<br> sign2";

?>

As you can see I've included all sorts of things to echo out whatever is in $_POST but apparently there is nothing there and this is the response I get:

sign1

Notice: Undefined index: tent in C:\wamp\www\mysite\oxifa/oxifat.php on line 16

Notice: Undefined index: zart in C:\wamp\www\mysite\oxifa/oxifat.php on line 17

Notice: Undefined index: tent in C:\wamp\www\mysite\oxifa/oxifat.php on line 18

Notice: Undefined index: zart in C:\wamp\www\mysite\oxifa/oxifat.php on line 19

sign2

three lines about the "setRequestHeader" are in comment status. If I include them, I don't even get sign1. No response. What I figure out from this is everything is OK but I don't seem to understand how to use the post method to pass data to php. How do I do this? I have read everything on the net. I only do not know what "setRequestHeader" is for. One more thing: If I put ?tent=zuzu&zart=gagi at the end of target URL, $_REQUEST thing works. But that's GET and not what I'm trying to do. What is the $_POST's deal?

Answer 1

Could you please try to invoke following code

function getXMLObject() {
  var xmlHttp = false;
  try {
    xmlHttp = new ActiveXObject("Msxml2.XMLHTTP");// For Old Microsoft Browsers
  }
  catch (e) {
    try {
      xmlHttp = new ActiveXObject("Microsoft.XMLHTTP");// For Microsoft IE 6.0+
    }
    catch (e2) {
      xmlHttp = false;// No Browser accepts the XMLHTTP Object then false
    }
  }
  if (!xmlHttp && typeof XMLHttpRequest != 'undefined') {
    xmlHttp = new XMLHttpRequest();//For Mozilla, Opera Browsers
  }
  return xmlHttp;// Mandatory Statement returning the ajax object created
}

var xmlhttp = new getXMLObject();//xmlhttp holds the ajax object

//use this method for asynchronous communication
function doRequest(params, callback) {
  if (xmlhttp) {
    xmlhttp.open("POST", "your_script.php?" + params, true);
    xmlhttp.onreadystatechange = function () {
      if (xmlhttp.readyState == 4) {
        if (xmlhttp.status == 200) {
          callback(xmlhttp.responseText);
        }
        else {
          alert("Error retrieving information (status = " + xmlhttp.status + ")
" + response);
        }
      }
    };
    xmlhttp.setRequestHeader('Content-Type', 'application/x-www-form-urlencoded');
    xmlhttp.send(null);
  }
}

and in your PHP script first thing off write

print_r($_POST);