我可以将多个链接传递给fopen，fread和feof吗？

Question

I have the following function :

    function doParse($parser_object) {
    $links=file("./fullsoccer.TXT", "r");
    $i=0;
    while(!empty($links[$i]))
    {
        set_time_limit(0);
        if (!($fp = fopen($links[$i], "r")));
        {
            //loop through data
            while ($data = fread($fp, 4096)) {
                //parse the fragment
                xml_parse($parser_object, $data, feof($fp));
            }
        }
        $i++;
    }
}

This code save a list of 507 links of XML data from fullsocce.txt into $links then I read the content of each file (link: online links) using fread and pass the $data to my main function which is xml_parse to parse and save the data using SAX parser . my problem is: just that last file of the array $links is passed to the function and parse the data , I want your help to know why it is working just with one file? please It is an emergency case

Answer 1

!($fp = fopen($links[$i], "r")

fopen returns FALSE on error so this check is only true at eof or an invild line. Maybe changing it to

 if (($fp = fopen($links[$i], "r") != FALSE)

I also noticed an extra ; and ) in if (!($fp = fopen($links[$i], "r"))); Maybe I'm just not matching properly.