dongxuan2577 2012-06-19 23:44
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前端mysql视图，用复选框删除条目？

I'm building off of a question I had asked and resolved earlier: front end mysql, deleting a row

Basically, I've got a front end where users can view a DB. Instead of having a delete button next to each row, I'd like to have a checkboxes that can be selected for multiple rows. Then, the user only clicks a single delete button and all the selected rows are removed. I don't know much php and mysql at all, so I'm not sure how to approach the code that I already have.

Currently, the onclick calls a delete function. Can anyone help?

I've got a php file that outputs the html for the mysql data into a long strong, the part I need to change is: 

$display_string .= "<td class='blank'><input type=\"button\" VALUE=\"Delete\" onclick='delFunction(" . $row['ID'] . ")' ></td>";

Next my delete function:

function delFunction(ID){
    // confirm delete
    if (!confirm(\"Are you sure you want to delete?\")) return false;

    var ajaxRequest;  // The variable that makes Ajax possible!


    try{
        // Opera 8.0+, Firefox, Safari
        ajaxRequest = new XMLHttpRequest();
    } catch (e){
        // Internet Explorer Browsers
        try{
            ajaxRequest = new ActiveXObject(\"Msxml2.XMLHTTP\");
        } catch (e) {
            try{
                ajaxRequest = new ActiveXObject(\"Microsoft.XMLHTTP\");
            } catch (e){
                // Something went wrong
                alert(\"Your browser broke!\");
                return false;
            }
        }
    }
    // Create a function that will receive data sent from the server
    ajaxRequest.onreadystatechange = function(){
        if(ajaxRequest.readyState == 4){
            var ajaxDisplay = document.getElementById('ajaxDiv');
            ajaxDisplay.innerHTML = ajaxRequest.responseText;
        }
    }

    var queryString = \"?ID=\" + ID


    ajaxRequest.open(\"GET\", \"delete_row.php\" + queryString, true);
    ajaxRequest.send(null); 
}
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1条回答 默认 最新

  • douli1854 2012-06-20 02:04
    关注

    To my understanding of your problem, I am posting some codes for both front and back ends

    Front-End Sample Code

    <body>
<form action="delete.php" method="post">
<input type="checkbox" name="del_chk[]">Item1
<input type="checkbox" name="del_chk[]">Item2
<input type="checkbox" name="del_chk[]">Item3
<input type="checkbox" name="del_chk[]">Item4
.
.
<input type="submit">
</form>

    ................

    Your back-end code would now be...

    <?php
if(isset($_POST['del_chk'])){
$chkbox=$_POST['del_chk'];
foreach($chkbox as $key=>$value) {

//Now you can get your value and use it in mysql delete statements


//for example
$del_query="DELETE FROM `yourtable` WHERE `pri_key`=$value;";
if(mysql_query($del_query)) {
echo "Successful Deletion of: ".$value;
}
else 
{
echo "Unsuccessful Deletion of: ".$value;
} 

} //end foreach
}
?>

    I don't know much of ajax. but you can use ajax to call this page..

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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