获取参数，通过PHP中的链接传递

Question

I get variable from http://localhost/match?id=1 via code:

<?
if (isset($_POST['id'])) {
    $id = $_POST['id'];
    $id = secure($id);
} else {
    echo "error";
    die();
}

And I get the error from my else statement. How to get the parameter, passed via the link?

Answer 1

Try this code:

<?
if (isset($_GET['id'])) {
    $id = $_GET['id'];
    $id = secure($id);
} else {
    echo "error";
    die();
}

Params, passed throught the link, are accessable trough the $_GET superglobal.

Info about $_GET on php.net.

Some explanations about $_GET vs $_POST on w3schools.com.