dpkk8687 2015-06-25 21:07
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使用jQuery将javascript变量传递给php

i am trying to pass JavaScript file variable to php to open the file in new window, but it seems, it is not working accurately

JavaScript code

function Open(){
    var file = prompt("Enter a File name to open with .txt");
    $.get( "php/OpenFile.php",
        file,
        function(result){
            console.log(result);
        }
    );
}

PHP Code

<html>
<body>
<?php
$file = $_GET['file'];

$file2 = file_get_contents($file);

echo "<script type='text/javascript'>window.open($file2)</script>";
?>

</body>
</html>
  • 写回答

3条回答

  • dqp99585 2015-06-25 21:10
    关注
    function Open(){
    var file = prompt("Enter a File name to open with .txt");
    $.get( "php/OpenFile.php",
        {file: file},
        function(result){
            console.log(result);
        }
    );
}

    In your Javascript, you are not sending the file name with an identifier. You can think of the Javascript object {file: file} as the html tag <input name='file' type='text' />

    If you are looking to open the file in a new window, no AJAX is needed.

    HTML:

    <a href="#" onclick="Open()">Open File</a>

    JavaScript:

    function Open() {
    var file = prompt("Enter a File name to open with .txt");
    window.open("php/OpenFile.php?file="+file);
}

    This may; however, be blocked by popup blockers.

    评论

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