PHP - 如何将*（任何内容）连接到当前URL

Question

I got a problem. I use curPageUrl() function to locate the link to my file and use it as 'active' to get some CSS effects.

This is the curPageUrl() code:

function curPageURL() {
    $pageURL = 'http';
    if ($_SERVER['HTTPS'] == "on") {
        $pageURL .= "s";
    }
    $pageURL .= "://";
    if ($_SERVER['SERVER_PORT'] != "80") {
        $pageURL .= $_SERVER['SERVER_NAME'] . ":" . $_SERVER['SERVER_PORT'] . $_SERVER['REQUEST_URI'];
    } else {
        $pageURL .= $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'];
    }
    return $pageURL;
}

And this is my html code:

<a href='home.php'><li class="<?php if (curPageUrl() == 'http://something/home.php') {echo 'active';} ?>">Home</li></a>

But the problem begins when I start using $_GET[] method so the next link http://something/home.php?some_get_code is no more 'active'.

How can I concatenate everything after home.php so my link still be active?

Answer 1

Use this:

<a href='home.php'>
    <li class="<?php if (strpos(curPageUrl(),'http://something/home.php') !== false) {echo 'active';} ?>">Home</li>
</a>

Use strpos function of PHP.