dongmai6666 2017-07-26 19:08
浏览 8
已采纳

PHP SQLSRV下拉列表错误

I am trying to populate dropdown list from SQL Query through sqlsrv but it is not working. What am i doing wrong?

<?php

$serverName1 = "kk12334";
$connectionInfo1 = array( "Database"=>"Fruits");
$conn1 = sqlsrv_connect( $serverName1, $connectionInfo1);
$sql1="SELECT [Name] as CName,[BName] as BName from Fruits";
$stmt1 = sqlsrv_query( $conn1, $sql1 );


while ($data=sqlsrv_fetch_array($stmt1, SQLSRV_FETCH_ASSOC))

{


  echo "<option value=";
    echo $data['CName'].", ".$data['BName'].;
    echo "<br />";
        echo $data['CName'].", ".$data['BName'];
    echo "</option>";

}

?>
  • 写回答

1条回答 默认 最新

  • doulang9953 2017-07-26 19:12
    关注

    You cannot place a <BR> inside an <option> tag.

    Try something like:

    while ($data=sqlsrv_fetch_array($stmt1, SQLSRV_FETCH_ASSOC))
    { $opt="$data[CName], $data[BName]";
       echo "<option value='$opt'>$opt</option>
    ";
    }
    

    And since you want a blank between your two variable values you need to enclose everything in ' to make sure both parts are assigned to value=.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 虚幻5 UE美术毛发渲染
  • ¥15 CVRP 图论 物流运输优化
  • ¥15 Tableau online 嵌入ppt失败
  • ¥100 支付宝网页转账系统不识别账号
  • ¥15 基于单片机的靶位控制系统
  • ¥15 真我手机蓝牙传输进度消息被关闭了,怎么打开?(关键词-消息通知)
  • ¥15 装 pytorch 的时候出了好多问题,遇到这种情况怎么处理?
  • ¥20 IOS游览器某宝手机网页版自动立即购买JavaScript脚本
  • ¥15 手机接入宽带网线,如何释放宽带全部速度
  • ¥30 关于#r语言#的问题:如何对R语言中mfgarch包中构建的garch-midas模型进行样本内长期波动率预测和样本外长期波动率预测