dongmai6666 2017-07-26 19:08
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PHP SQLSRV下拉列表错误

I am trying to populate dropdown list from SQL Query through sqlsrv but it is not working. What am i doing wrong?

<?php

$serverName1 = "kk12334";
$connectionInfo1 = array( "Database"=>"Fruits");
$conn1 = sqlsrv_connect( $serverName1, $connectionInfo1);
$sql1="SELECT [Name] as CName,[BName] as BName from Fruits";
$stmt1 = sqlsrv_query( $conn1, $sql1 );


while ($data=sqlsrv_fetch_array($stmt1, SQLSRV_FETCH_ASSOC))

{


  echo "<option value=";
    echo $data['CName'].", ".$data['BName'].;
    echo "<br />";
        echo $data['CName'].", ".$data['BName'];
    echo "</option>";

}

?>
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  • doulang9953 2017-07-26 19:12
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    You cannot place a <BR> inside an <option> tag.

    Try something like:

    while ($data=sqlsrv_fetch_array($stmt1, SQLSRV_FETCH_ASSOC))
    { $opt="$data[CName], $data[BName]";
       echo "<option value='$opt'>$opt</option>
    ";
    }
    

    And since you want a blank between your two variable values you need to enclose everything in ' to make sure both parts are assigned to value=.

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