dqdjfb2325 2018-03-09 12:40
浏览 67

使用Foreach进行MYSQL INSERT

When I want to add

data1 sum1
data2 sum2

to database, what is actually happening :

data1 data1
sum1 sum1
data2 data2
sum2 sum2

My form element is;

<input id="alan_" name="alanlar[]" type="text" class="form-control">
<input id="miktar_" name="alanlar[]" type="text" class="form-control">

And PHP;

foreach ($_POST['alanlar'] as $key => $value) {

            $baglanti->query(sprintf("INSERT INTO ders (ders_adi, ders_miktar) VALUES ('%s','%s')", ($value),($value)));
            $eklenen_ders_id = $baglanti->insert_id;

Jquery Code :

var sayac = 1;
    $(function () {
        $('#ekle').click(function () {
            sayac += 1;
            $('#dersler tbody').append(
                '<tr><th><strong>Ders ' + sayac + '</strong></th><td><input id="alan_' + sayac + '" name="alanlar[]' + '" type="text" class="form-control" /></td><td><input id="miktar_' + sayac + '" name="alanlar[]' + '" type="text" class="form-control" /></td><td><a href="#" class="sil btn btn-danger">Sil</a></td></tr> ');
        });

Thanks all.

  • 写回答

2条回答 默认 最新

  • douliao5467 2018-03-09 12:48
    关注

    Setting up the form control names sensibly greatly enhanced the form data processing on the server:

    HTML

    <input name="alanlar[0][alan]" type="text" class="form-control">
    <input name="alanlar[0][miktar]" type="text" class="form-control">
    <input name="alanlar[1][alan]" type="text" class="form-control">
    <input name="alanlar[1][miktar]" type="text" class="form-control">
    <!-- etc. -->
    

    PHP

    foreach ($_POST['alanlar'] as $set) {
      $alan = $set['alan'];
      $miktar = $set['miktar'];
      // ...
    }
    
    评论

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