duanfu6160 2017-10-27 08:31
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如何将字符串转换为变量并仍然获得良好的输出

How do i turn an string into variables and still get a good output.

$text = "showandreturn";

$disp = str_split($text, 2); 

$firstnum = 3;

for($b = 0; $b<$firstnum; $b++){

    $a = "$disp[$b]"; #showan

}

$b = "ENDED";

for($b = $firstnum; $b<sizeof($disp); $b++){

    $c = "$disp[$b]"; #dreturn

    echo = "$a$b$c";
}

my current output with this code is . andranetanurann .. And I want beter result like showanENDEDdreturn

Thanks for your time and understanding..

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3条回答 默认 最新

  • doupu9251 2017-10-27 08:55
    关注

    You are overwriting your variables every time it loops so only the result of the last loop is stored in the variable.

    This code should return the required output.

    $text = "showandreturn";
    $disp = str_split($text, 2);
    $num = 3;
    $a = '';
    $c = '';
    for($b = 0; $b<$num; $b++){
        $a .= $disp[$b];
    }
    $b = "ENDED";
    for($bn = $num; $bn<sizeof($disp); $bn++){
        $c .= $disp[$bn];
    }
    echo $a.$b.$c;
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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