<?php
$queryuser = "SELECT id, email, firstname, lastname, address, city, country FROM users WHERE role = 'client'";
$resultuser = $connection->query($queryuser);
if ($resultuser->num_rows > 0)
{
// output data of each row
while ($rowuser = $resultuser->fetch_assoc())
{
$id_user = $rowuser['id'];
$firstname = $rowuser['firstname'];
$lasttname = $rowuser['lastname'];
$email = $rowuser['email'];
$phone = $rowuser['phone'];
$city = $rowuser['city'];
$state = $rowuser['state'];
$address = $rowuser['address'];
?>
注意:尝试获取非对象的属性'num_rows'
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1条回答 默认 最新
- donglu9134 2019-01-17 19:48关注
Perhaps you've copied code from this page https://www.w3schools.com/php/php_mysql_select.asp
- Please understand code line by line first. You have not define
$connection
variable in your code (may be it is a intentional approach for security). - Your notice saying that you are trying to get
num_rows
property from the object$resultuser
but in this query$resultuser
is not a object due to any error/faults of your query because query() returns FALSE on failure and object on success. - To confirm, you can check your result set by using var_dump();
- Please replace this line if $resultuser->num_rows > 0 with
(!empty($resultuser->num_rows) && ($resultuser->num_rows > 0)))
解决 无用评论 打赏 举报 - Please understand code line by line first. You have not define
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