为什么会报错 [Error] ld returned 1 exit status ？？

Question

首先说明，不是编译器没有关闭的问题。

附代码供大佬检查。

#include <iostream>
using namespace std ;
void merges(double [] , int , double [] , int , double []) ;
int main()
{
    double numbers1[80] , numbers2[80] , numbers[80] ;
    int count = 0 ;
    for (int i = 0 ; i <= count ; i++)
    {
        if (count == 0)
        {
            cout << "输入第一个数组的元素个数\n" ;
            cin >> count ;  
            count = count - 1 ;
            cout << "依次输入第一个数组的元素\n" ;
        }
        cin >> numbers1[i] ;
    }
    int numbers1Size = count + 1 ;
    count = 0 ;
    for (int i = 0 ; i <= count ; i++)
    {
        if (count == 0)
        {
            cout << "输入第二个数组的元素个数\n" ;
            cin >> count ;
            count = count - 1 ; 
            cout << "依次输入第二组数组元素\n" ;
        }
        cin >> numbers2[i] ;
    }
    int numbers2Size = count + 1 ;
    merges(numbers1 , numbers1Size , numbers2 , numbers2Size , numbers) ;
    return 0 ;
}


void merges(double numbers1[80] , int numbers1Size , double numbers2[80] , int numbers2Size , int numbers[80]) 
{
    bool changed ;
    do
    {
        changed = false ; 
        for (int i = 0 ; i < numbers1Size - 1 ; i++)
        {
            if(numbers1[i] > numbers1[i+1])
            {
                double savings ;
                savings = numbers1[i] ;
                numbers1[i] = numbers1[i+1] ;
                numbers1[i+1] = savings ;
                changed = true ;
            } 
        }
    }while (changed) ;
    do
    {
        changed = false ;
        for (int i = 0 ; i < numbers2Size - 1 ; i++)
        {
            if(numbers2[i] > numbers2[i+1])
            {
                double savings ;
                savings = numbers2[i] ;
                numbers2[i] = numbers2[i+1] ;
                numbers2[i+1] = savings ;
                changed = true ;
            } 
        }
    }while (changed) ;
    int n1 = 0 , n2 = 0;
    for (int i = 0 ; i <= numbers1Size + numbers2Size -1 ; i++)
    {
        if (n1 <= numbers1Size - 1 && n2 <= numbers2Size - 1)
        {
        if (numbers1[n1] > numbers2[n2])
        {
            numbers[i] = numbers2[n2] ;
            n2++ ;
        }
        else
        {
            numbers[i] = numbers1[n1] ;
            n1++ ;
        }
        continue ; 
        }
        if (n1 > numbers1Size - 1)
        {
            for ( ; n2 <= numbers2Size - 1 ; n2++)
            {
                numbers[i] = numbers2[n2] ;
                i++ ;
            }
        continue ;  
        }
        if (n2 > numbers2Size - 1)
        {
            for ( ; n1 <= numbers1Size - 1 ; n1++)
            {
                numbers[i] = numbers1[n1] ;
                i++ ;
            }   
        }
    }
    cout << "\n\n" << "将两个数组合并后的元素按大小顺序排列如下: " ;
    for (int j = 0 ; j <= (numbers1Size + numbers2Size - 1) ; j++)
    {
        cout << numbers[j] << "  " ;
    }
    return ;
 } 

求大佬解答！！

Answer 1

void merges(double [] , int , double [] , int , double []) ;

void merges(double numbers1[80] , int numbers1Size , double numbers2[80] , int numbers2Size , int numbers[80]) {}

声明与实现的形参类型不一样了，好好看看