PHP日期功能仅适用于周一至周四[关闭]

Question

I have a delivery service that only picks up Monday through Thursday. I only want to give the user the next available three days as an option for a scheduled pickup.

My code works, but I was wondering if there was a more "efficient" way to write what Im trying to achieve?

$numericDay=date('N');
        if ($numericDay==1) {
            echo '<option value="' . date('Ymd', strtotime('+1 days')) . '">' . date('\T\o\m\o\o\w - F j, Y', strtotime('+1 days')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('+2 days')) . '">' . date('l - F j, Y', strtotime('+2 days')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('+3 days')) . '">' . date('l - F j, Y', strtotime('+3 days')) . '</option>';
        }
        if ($numericDay==2) {
            echo '<option value="' . date('Ymd', strtotime('+1 days')) . '">' . date('\T\o\m\o\o\w - F j, Y', strtotime('+1 days')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('+2 days')) . '">' . date('l - F j, Y', strtotime('+2 days')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('next monday')) . '">' . date('l - F j, Y', strtotime('next monday')) . '</option>';
        }
        if ($numericDay==3) {           
            echo '<option value="' . date('Ymd', strtotime('+1 days')) . '">' . date('\T\o\m\o\o\w - F j, Y', strtotime('+1 days')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('+next monday')) . '">' . date('l - F j, Y', strtotime('next monday')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('next tuesday')) . '">' . date('l - F j, Y', strtotime('next tuesday')) . '</option>';
        }
        if ($numericDay>=4 and $numericDay<=7) {
            echo '<option value="' . date('Ymd', strtotime('next monday')) . '">' . date('l - F j, Y', strtotime('next monday')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('next tuesday')) . '">' . date('l - F j, Y', strtotime('next tuesday')) . '</option>';
            echo '<option value="' . date('Ymd', strtotime('next wednesday')) . '">' . date('l - F j, Y', strtotime('next wednesday')) . '</option>';
        }

Thanks in advance for any insight!!!

Answer 1

Here is what you need ...

$dateTime = new DateTime();
$x = 0;
while ( $x < 3 ) {
    $dateTime->modify("+1 day");
    if ($dateTime->format("N") > 4)
        continue;
    printf("<option value=\"%s\">%s</option>
", $dateTime->format("Ymd"), $dateTime->format("l - F j, Y"));
    $x ++;
}

Output

<option value="20130225">Monday - February 25, 2013</option>
<option value="20130226">Tuesday - February 26, 2013</option>
<option value="20130227">Wednesday - February 27, 2013</option>