I have this php file which is fetch data from my database and place it into divs. this div created by while loop I want tow div only to be select then send the content to php file using Ajax. The code execute with no problem but there is no result!! Any help advance and I completely lost of mind !!!
while($row=mysqli_fetch_array($result)){
$so=$row[0];
$s=$row[1];
$m=$row[2];
$a=$row[3];
$b=$row[5];
$c=$row[8];
?>
<body>
<div id="all"> //start all
<div class="r"> //start r
<div id="e"><?php echo"{$s}"; ?></div>
<div id="b"><?php echo"{$m}"; ?></div>
<div id="a"><?php echo"{$a}"; ?></div>
<div id="b"><?php echo"{$b}"; ?></div>
</div> //end r
</div> //end all
<?php
} //end while
?>
<div id="show"></div>
script code
$(document).ready(function(){
$(".r").click(function(){
$data = $(this).text();
alert($data); //it work well
$.ajax({
url: "view.php",
type: "post",
data: {
you: $data
},
success:function(response){
$('#show').html(response);
}
});
});
});
view.php
<?php
if(isset($_post['you'])){
printf("ok"); //just to check
}
?>