dqjl0906 2017-02-05 22:52
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PHP-为什么我的数据被插入mySQL表两次?

When I run the php file below it inserts data into mysql table twice. I don't run the insert command again anywhere, both entries have unique ids. Any ideas why?

Dumb of me Here it is:

<?php
require "conn.php";
require "stripe-php-4.4.0/init.php";
$fname = $_POST['fname'];
$lname = $_POST['lname'];
$email = $_POST['email'];
$phonenum = $_POST['phonenum'];
$pin = $_POST['pin'];
$device = $_POST['device'];
$timeout = $_POST['timeout'];
$token = $_POST['stripeToken'];


// Set your secret key: remember to change this to your live secret key in production
// See your keys here: https://dashboard.stripe.com/account/apikeys
\Stripe\Stripe::setApiKey("secretkey");

// Create a Customer:
$customer = \Stripe\Customer::create(array(
  "email" => $email,
  "source" => $token,
));

// Save the customer ID and other info in a database for later.
$newCustID = $customer->id;
$insert_new_user = "INSERT INTO zeus_borrowers (fname,lname,email,phonenum,pin,stripecusid,timeout,device) VALUES ('$fname','$lname','$email','$phonenum','$pin','$newCustID','$timeout','$device')";
$result = mysqli_query($conn ,$insert_new_user);

if($conn->query($insert_new_user) === TRUE){
}
else{
    echo "Error: " . $insert_new_user . "<br>" . $conn->error;
}
$conn->close();
?>
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1条回答 默认 最新

  • dongyi1015 2017-02-05 23:13
    关注

    In the if statement it is inserting the row again.

    Solutions:

    (1)Remove if statement. Issue:Won't check for error now.

    (2)Place die(); after

    $result = mysqli_query($conn ,$insert_new_user);
    

    Issue:Won't check for error now.

    (3) Best option: Remove line

    $result = mysqli_query($conn ,$insert_new_user);
    

    If statement will query and check for error.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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