求助！C++程序无报错无输出

Question

#include<iomanip>
#include<iostream>
using namespace std;
int main()
{
    //start
    //添加必要的变量声明 
    int a[10][10] = {0}; 
    int t =1,n;
    //end
    cout<<"输入方阵的的行(列)值(1~10):"<<endl;
    cin>>n;
    //初始化方阵
    //start
    for (int i = 0;i <= n - 1;i++)
    {
        for (int j = 0;j <= i;i++)
        {
            a[i][j] = t;
            t++;
        }
    }
    //end
    cout<<"A方阵输出:"<<endl;
    //start    
    //A方阵元素输出采用形式cout<<setw(6)<<A方阵元素
    for (int i = 0;i <= n - 1;i++)
        for (int j = 0;j <= n - 1;j++)
            cout << setw(6) << a[i][j];
    //end
    //B方阵初始化
    //start
    t = 1;
    for (int j = 0;j <= 4;j++)
        for (int i = 3 - j;i <= 3;i++)
        {
            a[i][j] = t;
            t++;
        }
    //end
    //B方阵输出
    cout<<"\nB方阵输出:"<<endl;
    //start
    //B方阵元素输出采用形式cout<<setw(6)<<B方阵元素
    for (int i = 0;i <= n;i++)
        for (int j = 0;j <= n;j++)
            cout << setw(6) << a[i][j];
    //end
    return 0;
}

Answer 1

//初始化方阵
    //start
    for (int i = 0;i <= n - 1;i++)
    {
        for (int j = 0;j <= i;i++)/内层循环为什么是i++？不是j++?,为什么j的上限是i而不是n-1?是写的梯形矩阵？
        {
            a[i][j] = t;
            t++;
        }
    }
    //end

    cout<<"A方阵输出:"<<endl;
    //start    
    //A方阵元素输出采用形式cout<<setw(6)<<A方阵元素
    for (int i = 0;i <= n - 1;i++)
        for (int j = 0;j <= n - 1;j++)
            cout << setw(6) << a[i][j];   //输出也有问题，外层循环没有实现换行，你这样所有的矩阵元素都在一行
    //end

矩阵B同理