这样的事情有可能吗？

Question

<?php
$division=$row['mark'];
$pass="Passed";
if($division>=80 && $pass==include "result.php")// Result.php has two value: one is `Pass` and the other is `Fail`.
{
  echo "Letter";
}
elseif($division>=70 && $pass==include "result.php")
{
  echo "First";
}
else
{
  echo "Fail";
}
?>

What I want to output here is: if $division is equal to 80 and at the same time if $pass is equal to Passed, echo Letter. But if $division is less than 70, echo Fail; also $pass here equals to fail which is taken from result.php. I have been trying to output it with following code, but it does not work. It outputs FailFailFailFail when $division is less than 70.

Code for Result.php

<?php
   $eng=40;
   $mizo=40;
   $hindi=40;
   $maths=40;
   $ss=40;
   $science=40;

   if ($eng>=40 && $mizo>=40 && $hindi>=40 && $maths>=40 && $ss>=40 && $science>=40)
   {
   echo "<font color=green>Passed</font>";
   }
   else 
   {
   echo "<font color=red>Failed</font>";
   }
   ?>

Answer 1

Something like this will do. For your result.php, use the following:

 <?php
 $eng= 40;
 $mizo= 40; 
 $hindi= 40; 
 $maths= 40; 
 $ss= 40; 
 $science= 40; 

//  first group your variable into one array = $all
$all = array($eng, $mizo, $hindi, $maths, $ss, $science); 
// second, just iterate over them till you find one value -40
for($i=0; $i < count($all); $i++){
if($all[$i] < 40) $sum = 1;
}
?>

For output:

<?php include "result.php";?>
<?php 
$division=$row_['mark'];
$pass="Passed";
$test = (!empty($sum)) ? 'Failed' : 'Passed';
if($division>=80 && $pass==$test)
{
echo "Letter";
}
elseif($division>=70 && $pass==$test)
{
echo "First"; 
}
else
{
echo "Passed";
}
?>