PHP访问Mac上的共享文件夹

Question

I have to build the function to scan all folders, subfolders, and files on directory. I am able to do that now if its my own mac directories.

$parent_link = '/Users/myusername/Downloads';
$directory = dirToArray($parent_link);
var_dum($directory);

function dirToArray($dir) { 

   $result = array(); 

   $cdir = scandir($dir); 
   foreach ($cdir as $key => $value) 
   { 
      if (!in_array($value,array(".",".."))) 
      { 
         if (is_dir($dir . DIRECTORY_SEPARATOR . $value)) 
         { 
            $result[$value] = dirToArray($dir . DIRECTORY_SEPARATOR . $value); 
            //var_dump($result[$value]);
         } 
         else 
         { 
             $result[] = $value; 
         } 
      } 
   } 

   return $result; 
} 

However, How php access shared folder on Mac?

current situation :

I can access the shared folder on Mac using finder (with permission).

The folder is currently shared by mac server (LAN).

php is installed on my computer.

Answer 1

I changed the method of how I access the shared server. Instead of forcing it to access the shared folder by changing the path (which I'm still not able to figure it out), I am using php ftp. The working code is as follow :

$hostname = '192.168.X.X';
$username = 'username';
$password = 'password';
$conn_id = ftp_connect($hostname);
$login = ftp_login($conn_id, $username, $password);
$parent_link = 'Document';
if (!$conn_id) {
    echo 'Wrong server!';
    exit;
} else if (!$login) {
    echo 'Wrong username/password!';
    exit;
} else {
    $directory = dirToArray($conn_id, $parent_link);
    var_dump($directory);
}

function dirToArray($ftpConnection, $dir) { 

    $result = array(); 

    $cdir = ftp_nlist($ftpConnection, $dir); 
    foreach ($cdir as $key => $value) 
    { 
        $subs_value = substr($value, strlen($dir) + 1);
        // assuming its a folder if there's no dot in the name 
        if (strpos($value, '.') === false) {
            $result[$subs_value] = dirToArray($ftpConnection, $value);
        }
        else
        {
            $result[] = $subs_value;
        }
    } 
    return $result; 
}