doufang3001 2016-04-14 08:58
浏览 18

PHP和SQL不起作用?

$sql = mysqli_query($db, "SELECT COUNT(ID) from bruker");

if (!$sql) {
    while ($row1 = mysqli_fetch_array($sql, MYSQL_NUM)); {
        echo $row1;
    }
} else {
    echo "Funker ikke";
}

I cant get it to work, all I get is the: else "Funker ikke".

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4条回答 默认 最新

  • dongzhong2018 2016-04-14 09:01
    关注

    Your code are having two error there.
    First, it should be true condition only can get into the display loop. But you put the condition as !$sql means false only can get into the loop. So, you should change !$sql to $sql.

    Besides, after the While loop should not direct put the semicolon.

    You try see the following code

    $sql = mysqli_query($db, "SELECT COUNT(ID) from bruker");
    
    if ($sql) {
        while ($row1 = mysqli_fetch_array($sql, MYSQL_NUM))
        {
            echo $row1[0]; 
        }
    } 
    else {
        echo "Funker ikke";
    }
    
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