PHP语法错误，意外';' [关闭]

Question

Im geting an error message of Parse error: syntax error, unexpected ';' in E:\Websites\xxx.php line 29 Line 29 is

$_REQUEST["id"]);

Here are theadditional codes Thanks in advance

if
(
$mydb->execute("Update Diamond Set name = <name>, weight = <weight>, colour = <color>, cut = <cut>, where ID = <id>", 
$_REQUEST["name"], 
$_REQUEST["weight"],
$_REQUEST["color"],
$_REQUEST["cut"],
$_REQUEST["id"]);
$onloaddo = "alert('Saved existing diamond ".$_REQUEST["id"]."');";
$diamondid = "";
}
else
($_REQUEST["submitter"] == "Search")
{
if($_REQUEST["searchdiamondid"] != null && $_REQUEST["searchdiamondid"] != "")
{
$queryres = $mydb->query("Select id from diamond where id=%
$_REQUEST["searchdiamondid"]);
if ($queryres->countReturnedRows()==0)
$onloaddo="alert('diamond ID ".$_REQUEST['searchdiamondid']." not found!');";
else
{
$resultrow = $queryres->fetchRow();
$diamondid = $resultrow['diamondid'];
$name = $resultrow['name'];
$weight = $resultrow['weight'];
$colour = $resultrow['color'];
$cut = $resultrow['cut'];
$id = $resultrow['id'];
$formmode = 3;
}
}
}

Answer 1

Remove comma in <cut>,

change

$mydb->execute("Update Diamond Set name = <name>, weight = <weight>, colour = <color>, cut = <cut>, where ID = <id>",

to

$mydb->execute("Update Diamond Set name = <name>, weight = <weight>, colour = <color>, cut = <cut> where ID = <id>",