通过AJAX提交的表单，返回JSON响应[关闭]

Question

I have my form set up and the jquery written but I've have no idea what to write for the PHP that should be in mail.php.

Any help would be awesome

HTML:

<form id="contact-form" action="mail.php" method="GET">
   <fieldset>
       <label for="email">Email</label>
       <input type="email" name="email" id="email" required="">
   </fieldset>

   <fieldset>
       <label for="enquiry">Message</label>
       <textarea name="enquiry" id="enquiry" width="100%" height="100px" required=""></textarea>
   </fieldset>

   <fieldset>
        <input type="submit" name="submit" value="Submit Enquiry">
   </fieldset>

</form>

JQUERY:

$(document).ready(function(){

$("#contact-form").submit( function (){
    $.getJSON('mail.php',$(this).serialize(), function(data) { 
        if(data['success'] == 1)
        {
            $('#contact-form').html("<p class=\"success\">"+data['message']+"</p>");
        }
        else
        {
                alert(""+data['message']+"");
                $('#contact-form *').removeClass('error');
                for(key in data.errors)
                {
                    $('#'+key).addClass('error');
                }
        }
    });
    return false;
});

});

PHP:

?

Answer 1

Use this in server-side

parse_str($_GET["data"],$array);

mail($array["email"]);

in jquery

 $.getJSON('mail.php',{"data":$(this).serialize()}, function(data) { ...

                  or

var data=$("#contact-form").serialize();
$.ajax(
url:'mail.php';
{data:{"data":data},
datatype:"json",
success:(function(data){

   if(data['success'] == 1)
        {
            $('#contact-form').html("<p class=\"success\">"+data['message']+"</p>");
        }
        else
        {
                alert(""+data['message']+"");
                $('#contact-form *').removeClass('error');
                for(key in data.errors)
                {
                    $('#'+key).addClass('error');
                }
        } 
    })