伯爵和Foreach？ [重复]

Question

This question already has an answer here:

• PHP parse/syntax errors; and how to solve them? 17 answers

I am trying to count the number of rows I am selecting from the database and write a Foreach loop if the number of rows is greater than 1. I keep getting an unexpected ')' error. Why is this?

<?php
    if(isset($_SESSION['login_user'])) {
        $login_session = $_SESSION['login_user'];
        echo '<h1>Welcome '. $login_session .'</h1>';
    }

    echo '<table>';
    $sql_query = "SELECT * FROM Courses";
    $result = mysqli_query($dbconfig, $sql_query);
    $row = mysqli_fetch_array($result, MYSQLI_ASSOC);
    $count = mysqli_num_rows($result);

    if($count > 1) {
        foreach($result as $row)
            echo '<tr>'. $row['Title'] .'</tr>';
        }
    }
    echo '</table>';        
?>

The exact error is:

[12-Aug-2016 09:54:29 Europe/London] PHP Parse error:  syntax error, unexpected '}' in /home/etd/public_html/etd/single/courses.php on line 33

</div>

Answer 1

It's unexpected '}' error (curly braces).

Your foreach loop is missing the opening curly brace. It should be like this:

<?php
    if(isset($_SESSION['login_user'])) {
        $login_session = $_SESSION['login_user'];
        echo '<h1>Welcome '. $login_session .'</h1>';
    }

    echo '<table>';
    $sql_query = "SELECT * FROM Courses";
    $result = mysqli_query($dbconfig, $sql_query);
    $row = mysqli_fetch_array($result, MYSQLI_ASSOC);
    $count = mysqli_num_rows($result);

    if($count > 1) {
        foreach($result as $row) {  // this is where the curly bracket opening is missing
            echo '<tr>'. $row['Title'] .'</tr>';
        }
    }
    echo '</table>';        
?>

Without the opening there is one extra closing curly brace and as the interpreter told you - it is unexpected.