dongwopu8210 2014-12-05 06:06
浏览 38
已采纳

php嵌套while循环。 内环只能工作一次[关闭]

This is the code . Any help ??

<?php  

    //connect to the database 
        $con=mysql_connect("localhost","root","") or die("Error in connection");
        mysql_select_db("riffadb",$con)or die("Error in database");
    // 
        $sql1 ="select category_id,category_code from category";
        $res1 = mysql_query($sql1); 

        $sql2 = "select category_id1,product_id  from product";
        $res2 = mysql_query($sql2);
        $i=0;
        $j=1000;
        while($row1 = mysql_fetch_array($res1))
        {
            echo $row1['category_code'];
            echo '<br/>';
            while($row2 = mysql_fetch_array($res2))
            {   
                if($row1['category_code'] == $row2['category_id1'])
                {   
                    $sql3 = "update product set category_id = ".$row1['category_id']." where product_id = ".$row2['product_id'];
                    echo '<br/>';
                    mysql_query($sql3);
                }
            }
            $i++;
        }
        echo $i;
    ?>
  • 写回答

3条回答 默认 最新

  • doumen1883 2014-12-05 06:20
    关注

    I think you need to re-query res2 inside the outer loop, or at least reset the pointer. The second time through the outer loop you have nothing left in res2, since you've already reached the end

    In addition, with would be a lot more efficient if you setup the res2 query inside the outer loop and add a where clause so that you are only matching the category ID from the current row in res1.

    Hope this helps.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论
查看更多回答(2条)

报告相同问题?

悬赏问题

  • ¥15 牛顿斯科特系数表表示
  • ¥15 arduino 步进电机
  • ¥20 程序进入HardFault_Handler
  • ¥15 oracle集群安装出bug
  • ¥15 关于#python#的问题:自动化测试
  • ¥20 问题请教!vue项目关于Nginx配置nonce安全策略的问题
  • ¥15 教务系统账号被盗号如何追溯设备
  • ¥20 delta降尺度方法,未来数据怎么降尺度
  • ¥15 c# 使用NPOI快速将datatable数据导入excel中指定sheet,要求快速高效
  • ¥15 再不同版本的系统上,TCP传输速度不一致