PHP - 读取文件和回显结果

Question

I have /fonts/ folder full of .js files.

I know how to read this folder and list all the files there:

 $dir = "/fonts"; 
        if (is_dir($dir)) {     
            if ($dh = opendir($dir)) {
                while (($file = readdir($dh)) !== false) {
                    echo '<tr><td>'. $file .'</td></tr>';
                }
            closedir($dh);
            }
        }

But I don't want to write filenames but data they store.

The pattern inside looks like this:

NameOfTheFontFile_400_font.js:

(...) "font-family":"NameOfTheFont" (...)

So how to modify my first script to open-read each file and grab the font-family name instead of file name?

Thanks a lot!

Answer 1

From the php manual:

$lines = file($file);

Edit: This can probably be optimized, but to get the line with the font:

foreach ($lines as $line)
{
  if (strpos($line, 'font-family') !== false)
  {
    echo $line;
  }
}

You can dig further in that line using string functions or regular expressions to get the exact font name (using for example strpos()), but how to do that depends on the general format of the file.