1条回答 默认 最新
- douliang4858 2018-01-24 07:55关注
Try this :
foreach ($parts as &$part)
This will be passed by reference, but until now you were doing a copy.
本回答被题主选为最佳回答 , 对您是否有帮助呢?解决 无用评论 打赏 举报
Try this : foreach ($parts as &$part)
This will be passed by reference, but until now you were doing a copy.