doujupa7567 2017-07-03 10:14
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在PHP中读取JavaScript变量

I am looking for a way to either read an image src in PHP or read a JavaScript variable in PHP.

The plan: I have a webcam script in JavaScript that takes an image using the base64 Canvas method, but I need it to update a MySQL record using PHP.

After trying many methods; cookies, submit forms, ajax. I decided that making a post here was the best idea.

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  • doushijiao0679 2017-07-03 12:33
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    (!) Use with caution. This is a proof of concept. In PHP you should never just accept and compute client-side data without checking it for malicious code and sanitizing the input. (!)

    You could send it to PHP using AJAX by putting your base64-source into formData.

    Javascript:

    // ajax.js
    var xhr = new XMLHttpRequest(); // initialize a new XHR
    var formData = new FormData(); // initialize form data
    var myFile = 'data:image/png;base64,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';
    
    xhr.open('POST', '/requestHandler.php') // init your request
    xhr.onreadystatechange = function () {
    // check if the server was able to compute the XHR
        if(xhr.readyState === XMLHttpRequest.DONE && xhr.status === 200) { 
            // handle the response
            console.log(xhr.responseText) // log the PHP output
        }
    }
    
    // a form data element needs a descriptor/name and a value.
    formData.append('myfile', myFile);
    xhr.send(formData); // send your xhr to the server
    

    PHP:

    // requestHandler.php
    <?php
    if('$_POST') {
        echo $_POST['myfile']; // this is your image source
    }
    

    Further information:

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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