传递值时出现语法错误[关闭]

Question

I am trying to pass the value one form to another. I am getting ") missing" but I am not getting where I am going wrong. Is this the correct way to call all the parameters?

Uncaught SyntaxError: missing ) after argument list

$("#div1").load("http://ppp.gkdsjfgk.com/wp-content/themes/thestory/compare-form-site.php?loanamt=" + 
      <?php echo $_POST['loanAmt']; ?>."&occupation=" + 
      <?php echo $_POST['occupation']; ?>."&rateType=" + 
      <?php echo $_POST['rateType']; ?>."&age=" + 
      <?php echo $_POST['age']; ?>."&city=" + 
      <?php echo $_POST['city']; ?> );

Answer 1

You're using the wrong concatenator just after each of your PHP brackets ?>. The dot (the concatenator for PHP) should be replaced with + (the JavaScript concatenator) like this ?> +.

$("#div1").load(
    "http://ppp.gkdsjfgk.com/wp-content/themes/thestory/compare-form-site.php?loanamt=" + 
    <?php echo $_POST['loanAmt']; ?> + "&occupation=" + 
    <?php echo $_POST['occupation']; ?> + "&rateType=" + 
    <?php echo $_POST['rateType']; ?> + "&age=" + 
    <?php echo $_POST['age']; ?> + "&city=" + 
    <?php echo $_POST['city']; ?> 
);