如何将这个PHP代码转换为ruby（RoR）代码？ [关闭]

Question

I am new in ruby on rails. I am migrating from php to ruby. Now I have some php projects which are being converted into ruby code.But How can I convert this switch code to ruby on rails 4? function ajax($command) {

    switch ($command) {
        case 'page_reload':
            $this->ajax_delete_entries_of_current_uid();
            break;

        case 'labchem_products':
            $this->ajax_labchem_products();
            break;

        case 'labchem_carts':
            $this->ajax_labchem_carts();
            break;

        case 'labchem_customers':
            $this->ajax_labchem_customers();
            break;

        case 'products_selected':
            $this->ajax_products_selected();
            break;

        case 'products_total':
            $this->ajax_products_total();
            break;

        case 'products_delivery_info':
            $this->ajax_products_delivery_info();
            break;

        case 'labchem_orders':
            $this->ajax_labchem_orders();
            break;

        default: break;
    }
} 

Answer 1

case command
  when 'page_reload'      then ajax_delete_entries_of_current_uid()
  when 'labchem_products' then ajax_labchem_products()
  # or
  when 'labchem_carts'
    ajax_labchem_carts()
  # and so on ...
end

You don't need break. Only one or no when will be executes. If no when matches you could note an else to execute something.

In ruby the case will return the last value, so you could save it to a variable.

result =
  case command
    when 'a', 'b' then 1
    when 'c' then 2
    when 'd'..'z' then 3
    else
      0
  end

The comparison is done by object type and value (===).

case 1
  when '1' then 'a'
  when 1 then 'b'
end
# => "b"

More at ruby-doc.com and tutorialspoint.com.