dongmiao520892 2014-07-22 13:25
浏览 29

php中的csv数据库复制错误

I have this csv file:

NrSAT,StatoSAT,TipoServ,DataAtt,ImeiG,ImeiC,MarcaTer,ModelloTer,FamigliaG,DescrizioneG
SAT100000002572,in lavorazione,21/07/2014,8294121141143,8294121141143,Samsung,Nexus 4,Audio, Microfono Rott
SAT100000002573,in lavorazione,21/07/2014,8294121141143,8294121141143,Samsung,Nexus 4,Audio, Microfono Rot
SAT100000002574,in lavorazione,21/07/2014,8294121141143,8294121141143,Samsung,Nexus 4,Audio, Microfono Ro
SAT100000002575,in lavorazione,21/07/2014,8294121141143,8294121141143,Samsung,Nexus 4,Audio, Microfono R
SAT100000002576,in lavorazione,21/07/2014,8294121141143,8294121141143,Samsung,Nexus 4,Audio, Microfono Roto

I want to copy precisely this csv file in a database table. I tried this code but i have an error:

<?php


    $conn=mysql_connect("localhost","root","")or die (mysql_error());
    mysql_select_db("sat",$conn);

    if (isset($_POST['submit']))
    {
        $file = $_FILES ['file']['tmp_name'];

        $handle = fopen ($file,"r");
        while(( $fileop = fgetcsv($handle ,10000 ,",")) !== false)
        {

        $NumeroSAT = $fileop[0];
        $StatoSAT = $fileop[1];
        $TipoServizio = $fileop[2];
        $DataAttivazione = $fileop[3];
        $ImeiGuasto = $fileop[4];
        $ImeiConsegnato = $fileop[5];
        $MarcaTerminale = $fileop[6];
        $ModelloTerminale = $fileop[7];
        $FamigliaGuasto = $fileop[8];
        $DescrizioneGuasto = $fileop[9];

            echo $NumeroSAT;
            echo $StatoSAT;
            echo $TipoServizio;
            echo $DataAttivazione;
            echo $ImeiGuasto;
            echo $ImeiConsegnato;
            echo $MarcaTerminale;
            echo $ModelloTerminale;
            echo $FamigliaGuasto;
            echo $DescrizioneGuasto;



            $sql = mysql_query ("INSERT INTO gestite (NrSAT,StatoSAT,TipoServ,DataAtt,ImeiG,ImeiC,MarcaTer,ModelloTer,FamigliaG,DescrizioneG) VALUES ('$NumeroSAT ','$StatoSAT ','$TipoServizio','$DataAttivazione','$ImeiGuasto','$ImeiConsegnato,'$MarcaTerminale','$ModelloTerminale','$FamigliaGuasto','$DescrizioneGuasto')");

        }




    }   




    ?>

<html xmlns="http://www.w3.org/1999/xhtml"> 
<head> 
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> 
<title>Import a CSV File with PHP & MySQL</title> 
</head> 

<body> 
    <div id="mainWrapper">
        <form action="lol.php" method="post" enctype="multipart/form-data" > 
            <input type="file" name="file" /> 
            <br>
            <input type="submit" name="submit" value="submit" /> 
        </form> 
    </div> 
</body> 
</html>

This is the error that i have after thaht i loaded the csv file :

Notice: Undefined offset: 9 in C:\xampp\htdocs\Hop\lol.php on line 32

Some of you would know tell me why my code does not work? I have tried many things to fix it but I can not!

  • 写回答

2条回答 默认 最新

  • drt3751 2014-07-22 13:38
    关注

    The CSV you are loading indicates 10 columns when looking at the first line. However the following lines only hold 9 values.

    So, either you add a comma at the end of these lines, or if the last column is optional, use the following code:

    $DescrizioneGuasto = isset($fileop[9]) ? $fileop[9] : '';
    

    Thus, you would at least get rid of the error.

    However, it looks like in fact "StatoSAT" or "TipoServ" is missing in the data.

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