用php保存网址截图

Question

I have some urls daily , and need capture screenshot from these URLs. I want to save specific urls screenShot in my Host. Now I want to try it in localhost/wamp and also in linux host .

I try some libraries but weren`t successfully . I want to try with google api pagespeed v5 .

<?php
$url = 'mysite.com';
$response =     file_get_contents("https://www.googleapis.com/pagespeedonline/v5/runPagespeed?url=$url&screenshot=true");
$googlePagespeedObject = json_decode($response, true);
$screenshot = $googlePagespeedObject['screenshot']['data'];
$screenshot = str_replace(array('_','-'), array('/','+'), $screenshot);
echo "<img src=\"data:image/jpeg;base64,{$screenshot}\"     alt=\"Screenshot\" />";
file_put_contents('...', base64_decode($screenshot));

my error without any successfully image :

Warning: file_get_contents(https://www.googleapis.com/pagespeedonline/v5/runPagespeed?url=mysite.com&screenshot=true): failed to open stream: HTTP request failed! HTTP/1.0 403 Forbidden in

Answer 1

Here a Function to use for php screenshot :

function ScreenShotUrl($url){
$link = $url ;
$name = parse_url($link)['host'];
$googlePagespeedData = file_get_contents("https://www.googleapis.com/pagespeedonline/v2/runPagespeed?url=$link&screenshot=true");
$googlePagespeedData = json_decode($googlePagespeedData, true);
$screenshot = base64_decode($googlePagespeedData['screenshot']['data']);
$data = str_replace('_','/',$googlePagespeedData['screenshot']['data']);
$data = str_replace('-','+',$data);
$decoded = base64_decode($data);
file_put_contents('images/screenshots/'.$name.'.jpg',$decoded);
$file_name = "$name.jpg";
}