duanlan7239 2014-04-12 05:49
浏览 40
已采纳

PHP无法访问服务器上的数据库

I am having difficulty getting my PHP code to reference my database and display certain information within it. The error I am getting is "Unable to access database." I have poured over this code numerous times and cannot seem to find the solution. The first file (Approve Deny Prayer Request) references another file (Prayer Request) in order to draw the data. The idea is that I would be able to edit prayer requests and then click an "Approved" button that would edit the entry and re-save it into the database. Below please find both CGI files.

Thanks for the help.

Approve Deny Prayer Request

<table cellpadding="10">
<tr>
<td>First Name</td>
<td>Last Name</td>
<td>Prayer Request</td>
</tr>

<?php

$username="XXXXXX";
$password="XXXXXXXXX";
$database="prayer";

mysqli_connect('fbcaltusprayerorg.ipagemysql.com',$username,$password,$database);
@mysqli_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM Request";
$result=mysqli_query($query);
mysqli_close();

while ($row=mysqli_fetch_array($result)){
echo ("<tr><td>$row[Reg_F_Name]</td>");
echo ("<td>$row[Reg_L_Name]</td>");
echo ("<td>$row[Reg_Request]</td>");
echo ("<td><a href=\"cgi-bin/PrayerRequest.php?id=$row[id]\">Edit</a></td></tr>");
}
echo "</table>";

?>

Prayer Request

<?php

$username="XXXXX";
$password="XXXXXXXX";
$database="prayer";

mysqli_connect('fbcaltusprayerorg.ipagemysql.com',$username,$password,$database);
@mysqli_select_db($database) or die( "Unable to select database");
$query = "SELECT * FROM Request"; 
$result = mysqli_query($query);
$row = mysqli_fetch_array($result);
?>

<form method="post" action="cgi-bin/ApproveDenyPrayerRequest.php" />

<table>

<tr>
<td>First Name:</td>
<td><input type="text" name="first" value="<? echo "$row[Reg_F_Name]" ?>"></td>
</tr>

<tr>
<td>Last Name:</td>
<td><input type="text" name="last" value="<? echo "$row[Reg_L_Name]" ?>"></td>
</tr>

<tr>
<td>Prayer Request</td>
<td><input type="text" name="phone" value="<? echo "$row[Reg_Request]" ?>"></td>
</tr>

</table>

</form>
  • 写回答

1条回答 默认 最新

  • doujin8673 2014-04-12 06:07
    关注

    Don't use error suppression operator @ , it will hide the warnings and you will not be able to figure where the problem is..

    Rewrite your code like this for establishing the connection..

    <?php
    
    $username="XXXXX";
    $password="XXXXXXXX";
    $database="prayer";
    
    $link = mysqli_connect('fbcaltusprayerorg.ipagemysql.com', $username, $password, $database);
    
    if (!$link) {
        die('Connect Error (' . mysqli_connect_errno() . ') '
            . mysqli_connect_error());
    }
    
    echo 'Success... ' . mysqli_get_host_info($link) . "
    ";
    
    $query = "SELECT * FROM Request";
    $result = mysqli_query($link,$query); //<----- Added link
    $row = mysqli_fetch_array($result);
    ?>
    
    <form method="post" action="cgi-bin/ApproveDenyPrayerRequest.php" />
    
    <table>
    
        <tr>
            <td>First Name:</td>
            <td><input type="text" name="first" value="<? echo "$row[Reg_F_Name]" ?>"></td>
        </tr>
    
        <tr>
            <td>Last Name:</td>
            <td><input type="text" name="last" value="<? echo "$row[Reg_L_Name]" ?>"></td>
        </tr>
    
        <tr>
            <td>Prayer Request</td>
            <td><input type="text" name="phone" value="<? echo "$row[Reg_Request]" ?>"></td>
        </tr>
    
    </table>
    
    </form>
    

    Read more here from the PHP manual.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?

悬赏问题

  • ¥15 file converter 转换格式失败 报错 Error marking filters as finished,如何解决?
  • ¥15 ubuntu系统下挂载磁盘上执行./提示权限不够
  • ¥15 Arcgis相交分析无法绘制一个或多个图形
  • ¥15 关于#r语言#的问题:差异分析前数据准备,报错Error in data[, sampleName1] : subscript out of bounds请问怎么解决呀以下是全部代码:
  • ¥15 seatunnel-web使用SQL组件时候后台报错,无法找到表格
  • ¥15 fpga自动售货机数码管(相关搜索:数字时钟)
  • ¥15 用前端向数据库插入数据,通过debug发现数据能走到后端,但是放行之后就会提示错误
  • ¥30 3天&7天&&15天&销量如何统计同一行
  • ¥30 帮我写一段可以读取LD2450数据并计算距离的Arduino代码
  • ¥15 飞机曲面部件如机翼,壁板等具体的孔位模型