PHP网格类型数组获取行或列

Question

This may sound like a silly question and I'm not thinking hard enough,

Or its harder than i think...

Say i have a array of numbers like:

$table = array(
'5','2','1','4','4','4',
'1','2','4','2','1','1',
'3','4','3','1','4','4',
'1','4','2','S','4','4',
'1','2','4','2','1','1',
'5','2','6','4','8','1'
);

S = where I want to get either the row or column based on where "S" is.

I know i can get where S is.

by doing:

$start = array_search('S', $table);

The ''grid'' this array is based on,The S can can be anywhere.

And the grid itself can be different sizes length and width.

How would i go about getting the whole row or column.?

(IE:S is in column 3 : 4,2,1,S,2,4)

(IE:S is in row 3 : 1,4,2,S,4,4)

Just a hint in the right direction would be helpful, Don't need to go all out for me.

Or a idea on how to approach this.

Answer 1

Here is a hint:

$table[] = array();
$table[][0] = array(5,2,1,4,5);
$table[][1] = array(1,5,2,3,3);
$table[][2] = array(1,2,'s',4,5);

You will need an array of arrays to have an x/y search.

Your x is the nth element in the outer array.

Your y is the nth element in the inner array.