dougao1106 2016-07-15 23:40
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PHP有对象返回不同的对象

In a few different places I call:

$model=NEW MakeCall($form);

I have updated the MakeCall class with several changes that I want to take affect after a given date. I renamed the original class MakeCallOld

How can I leave my calls to:

$model=NEW MakeCall($form);

intact and within MakeCall do this:

class MakeCall
{ ...

    public function __construct($form)
    {
        //Use Legacy MakeCallOld for stuff before 2016-10-01
        if ($form['date']<'2016-10-01') {
            $object=NEW MakeCallOld($form);
            return $object;
        }

        $this->perform several functions and set variables...

This currently just returns an empty object of class MakeCallOld but it does not appear to run the constructor in MakeCallOld as all properties are empty. I would just like the entire object of MakeCallOld dropped into $model.

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2条回答 默认 最新

  • dtio35880438 2016-07-16 00:02
    关注

    What you need is a static factory constructor. This is the way you should be doing it to add initialization logic or switch constructors depending on the argument.

    class MakeCall
    {
    
        public function __construct($form)
        {
            $this->form = $form;
        }
    
        public function showForm(){
            echo $this->form;
        }
    
    
        public static function create($form){
            //put logic for picking object or whatever here!
            $object = new MakeCall($form);
            //Do more initializing if you want here!
            return $object;
    
        }
    }
    
    $form = "asdasd";
    $model= MakeCall::create($form);
    $model->showForm();
    
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