duanpang5583 2015-04-09 18:52
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Codeigniter - 从函数返回一个anchor()

probably a newb question here, but how do I return a CI anchor() call from within a function. I want to "hide" a button if a variable is set to a certain value. CI's URL helper documentation: https://www.codeigniter.com/user_guide/general/helpers.html

A pseudo example that won't work (can't return the URL helper anchor('',''):

$prevAvailCompID = 0;

function hideButton($prevCompID)
{
    if($prevCompID == 0)
    {
        return anchor('/getcomps/getSpecificComp/'.$prevCompID , 'PREV COMP');
        //I've also tried return echo anchor(...)
    }

}

further down on the page:

<div id="prevBtnContainer"><? hideButton($prevAvailCompID); ?></div>
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1条回答 默认 最新

  • dtpk04526211 2015-04-09 19:09
    关注

    You don't need to return the anchor() function. You can just use as this

    UPDATED CODE

    public function test(){
    
        ?>
        <h1>test H1</h1>
        <div id="prevBtnContainer"><?php $this->hideButton(0); ?></div>
        <div id="1prevBtnContainer"><?php $this->hideButton(1); ?></div>
        <?php
    
    }
    
    private  function hideButton($prevCompID)
    {
        if($prevCompID == 0)
        {
            echo anchor('/getcomps/getSpecificComp/'.$prevCompID , 'PREV COMP');
        }
    }
    

    I've tested this in my CodeIgniter and its working.

    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

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