dongrouli2667
2012-05-07 08:43 阅读 8

在PHP中加载和读取此XML中的元素

http://pastebin.com/hXuHpcUQ

Is what I have..

How can I load and read the data?

so for each node, I could do something like:

foreach($nodes as $node)
{
    echo $node->getElementsByTagName("url") . "<br />";
}

But how should $nodes be defined to grab alle the <node type="link">'s?

This is what I have started out and currently got:

    $doc = new DOMDocument();
    try
    {
        $doc = new DOMDocument();
        $doc->loadXml(file_get_contents('new.xml'));
    }catch(Exception $e)
    {
        continue;
    }

I would like to output the value in <url> inside each <node></node> element

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2条回答 默认 最新

  • 已采纳
    dongqucheng3851 dongqucheng3851 2012-05-07 08:47

    I would use SimpleXML - should be something like.

    $xml = simplexml_load_file('new.xml');
    foreach ($xml->node as $node) {
      echo $node->url;
    }
    

    (untested..)

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  • dongqiu9018 dongqiu9018 2012-05-07 08:54

    You should read about DOMXPath

    Your query will look like (not tested):

    $nodes = $xpath_obj->query("//node[type='link']/url");
    
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