drexlz0623 2013-01-01 14:44
浏览 45
已采纳

Yii覆盖createUrl但保留参数

I am extending and overwriting the createUrl method to make pretty URLs.

Here is a snippet:

public function createUrl($manager, $route, $params, $ampersand) {
        if($route == 'widget/view'){
            $widget = Widget::model()->findByPk($params['id']);
            return 'widget/' . $params['id'] . '/' . SEOUrlRule::slug($widget->title);
        }
}

Lots of things don't matter much here. And I removed irrelevant parts.

It works fine. However, sometimes the method may be called with additional parameters such as an anchor tag, or GET parameters to put at the end of the URL.

Using my method, these parameters will be lost. To pass them forward in the new URL, do I have to re-do whatever the original createUrl method did manually? Or is there a nice object oriented way to pass the job along to a competent method?

  • 写回答

1条回答 默认 最新

  • dsvjmc0907 2013-01-01 20:00
    关注

    You've made every argument required - is that intentional?

    You can have Yii construct the parameter string by using the createUrl from CApplication, e.g.:

    public function createUrl($manager, $route, $params, $ampersand) { 
            if($route == 'widget/view'){
                $widget = Widget::model()->findByPk($params['id']);
                $url = 'widget/' . $params['id'] . '/' . SEOUrlRule::slug($widget->title);
                return Yii::app()->createUrl(trim($url,'/'),$params,$ampersand);
            }
    }
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
    评论

报告相同问题?