如果语句比较整数

Question

I have some if statements that read a variable from my mysql database and then echo out a number based on that variable. For some reason, the code below only echos out "1" and I dont know why. ($x is 670, but it still echos out 1)

CODE:

 //connect to database and assign $x a int from database
 if ($x<=100){
 echo 1;
 }

 if ($x>=500 && $x<1000){
 echo 2;
 }

 if ($x>=1000 && $x<2500){
 echo 3;
 }

 if ($x>=2500 && $x<5000){
 echo 4;
  }

 if ($x>=5000 && $x<7500){
 echo 5;
 }

 if ($x>=7500  && $x<100000){
  echo 6;
 }

 if ($x>=10000){
 echo 7;
 }

EDIT: I did something stupid in my code with connecting to the DB. Thanks for your help anyway. I appreciate it.

Answer 1

It appears it's not the value you're expecting (int value of 670).

1. Less than or equal to 100? Yes: echo 1. This tells you that indeed the value is not an int value of 670.
2. The rest fail their boolean tests, as they don't pass those conditions.

To troubleshoot, try:

echo $x;

Perhaps explicitly cast that value as/after it comes out of your call to MySQL:

$x = (int)$x;