doudeng2016 2015-11-22 23:11
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mysql和php表单和连接[关闭]

this seems to be correct but I'm missing it somehow.

form in a demo-form.php file

<form action="test.php" method="post" />   
<p>Name: <input type="text" name="name" /></p>
<p>Email: <input type="text" name="email" /></p>
<input type="submit" value="Submit" />
</form>

code in a test.php file

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "forms1";

// Create connection
$conn = new mysqli($servername, $username, $password, $dbname);
// Check connection
if ($conn->connect_error) {
die("Connection failed: " . $conn->connect_error);
}

$sql = "INSERT INTO per_Info (name, email)
VALUES ('Test', 'test@example.com')";

if ($conn->query($sql) === TRUE) {
echo "New record created successfully";
} else {
echo "Error: " . $sql . "<br>" . $conn->error;
}

$conn->close();
?>

The problem: it inserts 'Test', 'test@example.com' into the database (under "name" and "email") instead of whatever name I actually type into the form, in other words, if I type "John" and "John@test.com in the Name field on the form it will only insert 'Test', 'test@example.com' and not "John", etc.

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2条回答 默认 最新

  • dpowhyh70416 2015-11-22 23:15
    关注

    You post data with a form and that data can be retrieved by using $_POST['inputname']

    <?php
    
        $stmt = $conn->prepare("
           INSERT INTO per_Info
            (name, email) 
           VALUES 
            (?, ?)
        ");
    
        $stmt->bind_param("ss", $_POST['name'], $_POST['email']);
    
        if($stmt->execute()){
          echo "New record created successfully";
        }
    
    ?>
    
    本回答被题主选为最佳回答 , 对您是否有帮助呢?
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